tag-widget

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tag-widget Tag widget

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A tag form, use it with taggable behvior

Resources ¶

Home page

Documentation ¶

Requirements ¶

Yii 1.0 or above
Installation

Change Log ¶

August 11, 2010 ¶

Initial release.

1 0

10 followers

1 983 downloads

Yii Version: 1.1

License: BSD-2-Clause

Category: User Interface

Tags:

Developed by: mech7

Created on: Aug 12, 2010

Last updated: 13 years ago

Downloads

tag_0.1.zip

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User Contributed Notes 3

#10549

0 0

FIx that works for me

In the file TagView.php, delete the line

$jui=Yii::app()->getAssetManager()->publish(Yii::getPathOfAlias('zii.vendors.jui').'/js/jquery-ui.min.js');

And replace

$cs->registerScriptFile($jui);

with

$cs->registerCoreScript('jquery.ui');

xtranophilist at Nov 4, 2012, 8:59:56 AM

#11180

0 0

My fix

replace all into

$tag_it_js=Yii::app()->getAssetManager()->publish($tag_it.'/tag-it.js');
$tag_it_css=Yii::app()->getAssetManager()->publish($tag_it.'/tag-it.css');

Yii::app()->clientScript
  //->registerCoreScript('jquery') FIX
  ->registerCoreScript('jquery.ui')
  ->registerScriptFile($tag_it_js)
  ->registerCssFile($tag_it_css)
  ->registerScript($id,'
    $("#'.$id.'").tagit({
        tags: '.$tags.',
        url: "'.$url.'"
    });
', CClientScript::POS_READY);

$tag_it - it`s my variable from widget

public function run()
    {
        $this->tags = json_encode($this->tags);
        // this method is called by CController::endWidget()
        $this->render('TagView', array(
            'id' => $this->id,
            'tags' => $this->tags,
            'url' => $this->url,
            'tag_it' => dirname(__FILE__),
            'title' => $this->title,
        ));
    }

Mirocow at Dec 24, 2012, 12:34:30 AM

#16524

0 0

Formatting the dropdown

I've finally got this working thanks to many of the posts in the forum for this extension, especially Aceman3000 who put me on the trail of creating a json.php. However, using that, as specified by Aceman, gives me a dropdown with three lines for each potential match as you might expect from his code which specifies that id, label, and value be echoed.

[<?php if($tags){
$total = count($tags) - 1;
foreach ($tags as $i =>$tag){
    //echo $tag->name;
    echo '{';
    echo '"id": "'.$tag->id.'",';
    echo '"label": "'.$tag->name.'",';
    echo '"value": "'.$tag->name.'"';
    echo '}';
    if($total !== $i){
        echo ',';
    }
}

}?>]

What I'd like to do is display just the label much like more traditional, HTML-generated dropdowns with the id and value hidden behind it. Unfortunately, my jQuery/JavaScript skills are about zilch. Can anyone help me with how to achieve that?

LarryTX at Mar 2, 2014, 5:39:44 PM

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